Direction A — Thickening the Action → Map F bridge (A1–A4)
Research programme after Direction 1: mode-space/Wilsonian toy for W=Q₃+n_Y; solar=4 light-sector bridge; S₄₀=Q₃+Q₅ sum-shell; force kernels ↔ F locks. SymPy spt_map_f_direction_a.py. Honest: not full path-integral continuum proof.
spt_map_f_direction_a.py · _plus.py · _next.py.§1 Why Direction A (after Map F)
Map F is already useful: shared locks, family kills, Explorer columns. The scientific gap peers will ask first is: is shell 13 only a counting slogan, or an effective structure read off the Action? Direction A attacks that gap in four sub-tracks without inventing Law 81.
| Track | Question | Status after this page |
|---|---|---|
| A1 | Why denominator = Q₃+n_Y? | CLOSED toy (mode space ⊕) |
| A2 | Why solar tooth = 4 from S? | CLOSED algebra + light 2×2 |
| A3 | Why S₄₀ = Q₃+Q₅ (flavor×cosmo)? | CLOSED sum-shell uniqueness |
| A4 | Tr(J·Ṙ) forces ↔ F locks? | CLOSED capacity + assignment |
§2 A1 — Mode-space / Wilsonian toy for W
Idea. After integrating out UV yao not in the EW projection, the IR counting space of mixing channels is a direct sum:
H_EW ≅ H_trigram ⊕ H_Y
dim H_trigram = Q₃ = 8
dim H_Y = n_Y = Q₃ − n_W = 5
dim H_EW = W = 13
sin²θ_W^tree = n_W / dim(H_EW) = 3/13Why not a pure sublattice of Q₇? W=13 does not divide Q₇=128, so the shell is not “every 13th vertex.” That supports the ⊕ sum of two budgets reading over a pure quotient. False shells {8, 12, n_W+n_Y=8, 16} fail the Action filter d=Q₃+n_Y.
§3 A2 — Solar tooth 4 from fermion / light sector
Four routes coincide at 4 (N2 theorem + light sector):
- R-A Q₃/2 = 4 — half of trigram cell (solar projects on half Q₃).
- R-B n_Y−1 = 4 — hypercharge budget minus vacuum pole.
- R-C n_W+1 = 4 — next ordered role after weak generators on W.
- R-D 2×2 = 4 — with m_ν1=0, effective solar 2ν block: 2 massive light states × 2 mixing slots (fermion-term story of S).
Identity I1: sin²θ₁₂ − sin²θ_W = 1/13 still holds. Full Feynman derivation of “why half Q₃” remains open (same honesty as N2 wiki).
§4 A3 — S₄₀ = Q₃ ⊕ Q₅ (flavor × cosmo sum-shell)
Reading (not product Q₃·Q₅). Two orthogonal counting spaces on the cascade ladder:
Flavor geometry ~ Q₃ = 8
Cosmo ladder step ~ Q₅ = 32
S₄₀ = dim(H_flavor ⊕ H_cosmo) = 8 + 32 = 40
λ = N_gen² / S₄₀ = 9/40
h = N_gen·(Q₃+1) / S₄₀ = 27/40
h/λ = 3 EXACTAmong power-of-two sum-shells Q_i+Q_j that host (9/d,27/d) with h/λ=3, the Action-motivated pair is the adjacent ladder rungs Q₃+Q₅ (flavor shell + next cosmo shell). Dynamical “why sum not product” from full cascade EOM remains open.
§5 A4 — Rotation term, four kernels, F locks
Action term ½Tr(J·Ṙ) + unified-force Law 42: generator capacity on Q₇ is 14 (yao-pair). SM uses 12 (8+3+1); gravity uses spin-2 frame (+2 geometric) — no fifth SU(N).
| Kernel | Count | Map F lock / form |
|---|---|---|
| SU(2) weak | 3 | W=13 · tooth 3 → 3/13 |
| U(1)_Y → EM | 1 (+ n_Y budget 5) | 137 = Q₇+Q₃+1; feeds W |
| SU(3) strong | 8 | Layer C cascade / α_s |
| Spin-2 gravity | 2 (frame) | Layer B/D hierarchy |
Open: full propagator Prop_X(r) derived from S for each kernel (Law 42 quantitative upgrade).
§6 Bridge status matrix
| Track | Closed now | Still open |
|---|---|---|
| A1 | Mode-space ⊕ toy; false-shell filter | Continuum Wilsonian fixed point |
| A2 | N2 four routes = 4; I1 | Feynman solar form factor |
| A3 | S₄₀ as Q₃⊕Q₅; h/λ=3 | Dynamical sum rule from EOM |
| A4 | 14-cap; kernel→lock table | Prop_X(r) from S |
§7 What you may claim (and may not)
- May: Map F shells have mode-space / sum-shell / capacity stories consistent with Action integers; SymPy PASS; PDG is OUTPUT only.
- May: Direction A reduces the “slogan only” critique relative to bare A0–A5 packaging.
- May not: “Full path-integral derivation of F from S is complete.”
- May not: New free parameters or Law 81.
§8 Direction A+ — Tier-B scoreboard (Đợt 61)
Next-step script spt_map_f_direction_a_plus.py upgrades discrete bridge claims and classifies tiers honestly:
| Claim | Tier | Result |
|---|---|---|
| A1+ EW-preserving decimation keeps dim H_EW = W = 13 | B-EXACT | PASS |
| A3+ ∂W/∂d₀ = ∂S₄₀/∂d₀ = 0 (shells ⟂ cascade slope) | B-EXACT | PASS |
| A4+ 137, 3/13, h/λ=3, capacity 14 | B-EXACT | PASS |
| A4+ α_EM, α_W, hierarchy, sin²θ_W vs PDG | B-PASS | PASS (Δ < 1% / scheme band) |
| Bridge+ δ_RG = 1/(1024π); IR = 3/13+δ_RG | B-EXACT + B-PASS OUTPUT | PASS (IR Δ ~0.06% PDG) |
| Continuum Wilsonian fixed point / full path-integral | OPEN (not Tier-B) | Not claimed |
| α_s zero-calibration ab initio | OPEN / A-track | Not claimed here |
Still next (not Tier-B yet)
- Continuum block-spin fixed point with full Euclidean invariance.
- Path-integral derivation of dim H_Y = 5 from ∫𝒟φ e^{iS}.
- Pre-reg FC-MF1–4 as external experimental judges.
§9 Reproduce offline
Direction A + A+ verification
A: six stages PASS. A+: Tier-B scoreboard PASS (EXACT + PASS). Continuum OPEN.
pip install sympy numpy && python3 scripts/spt_map_f_direction_a.py && python3 scripts/spt_map_f_direction_a_plus.py && python3 scripts/spt_master_map_f_from_action.py && python3 scripts/spt_master_map_n2_solar.pyDon't want to install Python? Paste the prompt straight into Grok / Claude / ChatGPT / Gemini — the AI fetches the public script URL below and independently verifies each assertion in ~30 s. Open grok.com or claude.ai , paste, send.
⚠️ AI can be wrong — running the Python above is the only 100% certain check. Full AI guide →
§10 Bottom line
spt_map_f_direction_a.py + _plus.py — not scoreboard volume.
Comments — Direction A — Thickening the Action → Map F bridge (A1–A4)