Map F — Easy full guide: what it is, the conditions, Tier-B proof
Plain bilingual guide to Master Map F: lock-and-tooth picture, closed forms 3/13 and 9/40, explicit package P (the conditions), Tier-B EXACT theorems, L2_STRICT fail, spectral reading of n_w, referee-safe claim, and SymPy reproduce kit. Not a new Law — a reading + honesty page.
spt_map_f_tier_b_proof.py).1. The real question (not “pretty numbers”)
SPT writes several measured quantities as Bagua fractions that look beautiful:
sin²θ_W (tree) ≈ 3/13
sin²θ_12 ≈ 4/13
n_T ≈ 3/13
Cabibbo λ ≈ 9/40
Hubble proxy h ≈ 27/40The scientific question is not “do they match PDG roughly?” but:
Is this a forced law under clear rules — or a lucky coincidence of integers?
Map F is the name of the single rulebook that tries to answer that with one map, not five independent fits.
2. What is Map F? (lock and tooth)
Write every constant as a fraction:
quan sát = TỬ SỐ / MẪU SỐ
= “răng” / “cỡ ổ khóa”F is one function:
F(lĩnh vực, vai trò đo) → phân số Bagua
(không nhét số PDG vào vế phải; PDG chỉ để kiểm SAU)| What we measure | F says | Lock (denom) | Tooth (num) |
|---|---|---|---|
| Weinberg angle (tree) | 3/13 | 13 | 3 (weak weight) |
| Solar sin²θ₁₂ | 4/13 | 13 | 4 (N2 lock) |
| GW tilt n_T | 3/13 | 13 | 3 (same as weak) |
| Cabibbo λ | 9/40 | 40 | 9 = 3² |
| Hubble proxy h | 27/40 | 40 | 27 = 3·9 |
3. The conditions — package P (this is the important part)
Think of P as the rulebook of the game. The theorems say: if you accept the whole rulebook, then the fractions lock.
P0 — Bagua integers only (no PDG as input)
Allowed building blocks: (Q_n = 2^n) (8, 16, 32, 64, 128…), binomial counts, and pure math like √7. Forbidden as inputs: CODATA α, PDG masses, hand-tuned knobs to match data.
P1 — Split 7 yao as 3 + 1 + 3
| Part | Count | Role (assignment) |
|---|---|---|
| Space | 3 | 3 spatial directions |
| Time | 1 | one arrow of time |
| Internal | 3 | internal axes (for counting) |
This split is a structural choice (STRUCT), not forced by “only powers of two.” Without it, there is no internal sector to count weak weight from.
P2 — R_axis: n_w = number of internal axes (= 3)
n_w := i = 3Spectral reading (Tier-B under P1): on the internal subcube (Q_i), the Laplacian spectral gap has multiplicity (i). So (n_w) = “number of weight-1 flip directions inside” = 3. This avoids typing the letters S-U-(2), but it is still a counting rule, not a free miracle.
P3 — Residual budget n_Y
n_Y := Q_3 − n_w = 8 − 3 = 5Inside the 8-cell trigram budget, remove the weak weight 3; 5 channels remain (hypercharge-style residual).
P4 — EW shell W (critical rule)
W := Q_3 + n_Y = 8 + 5 = 13
// NOT W = n_w + n_Y = 3 + 5 = 8
// Shell = trigram cell + residual Y
// Weak weight sits in the NUMERATOR onlyTree Weinberg angle:
sin²θ_W^tree = n_w / W = 3/13P5 — Flavour/cosmo shell S (minimal Q₃+Q_k)
Honest fact: the pair ((9/d,\,27/d)) with (h/\lambda=3) works for every (d>27). That alone does not pick 40. We need the shell rule:
S = Q_3 + Q_k (k ≥ 3)
with 0 < 9/S < 1 and 0 < 27/S < 1
and S minimal
→ only k=5 survives as minimal: S = 8+32 = 40P6 — Numerators on shell W
| Numerator | Value | Role |
|---|---|---|
| n_w | 3 | weak weight |
| n_sol | 4 | N2 lock (four routes = 4) |
| n_tilt | 3 | same as n_w on shared shell |
sin²θ_12 = 4/13
n_T = 3/13
I1: n_T ≡ sin²θ_W
I2: sin²θ_12 − sin²θ_W = 1/13P7 — Numerators on shell S
λ = 3² / S = 9/40
h = 3·(Q_3+1) / S = 27/40
h/λ = 3 EXACTP8 — Finite class R of Bagua denominators
Only denominators built from (Q_a), (Q_a+Q_b), (Q_a+k) in a fixed range. Then impose:
- U_NUM — fix numerators {3,4,3} on one denom and {9,27} on another
- U_SHELL — force denoms to be exactly W=13 and S=40
| Constraint pack | How many maps left? |
|---|---|
| U_WEAK (very loose) | ~ millions |
| U_NUM only | ~ thousands |
| U_NUM ∩ U_SHELL | exactly 1 |
4. Conditions in one line
BẮT BUỘC (package P)
Q_n = 2^n
7 hào = 3 + 1 + 3
n_w = 3 (trục nội / gap mult)
n_Y = 5
W = 8+5 = 13 ← shell EW
S = 8+32 = 40 ← shell flavour/cosmo (min Q3+Qk)
tử số 3,4,3 trên W và 9,27 trên S
class R hữu hạn + U_NUM ∩ U_SHELL
⇒ Map F duy nhất
3/13, 4/13, 3/13, 9/40, 27/40 (Tier-B EXACT)
KHÔNG NẰM TRONG ĐIỀU KIỆN
PDG · continuum Action · “chỉ số đẹp không luật chơi”5. What “Tier-B EXACT proof” means (and does not mean)
| Term | Plain meaning |
|---|---|
| Tier-B EXACT | Algebraic identity under explicit package P; no PDG as input; Δ ≡ 0 |
| STRUCT | A structural choice we state (e.g. 3+1+3) — reasonable, not pure number theory |
| OPEN | Not proved (continuum Action → P; why Nature is Q₇) |
Proved Tier-B under P (scripts): shells (13,40); closed forms; identities I1–I2; N2 lock; unique F in class R; L2_STRICT fails (capacity alone does not pick (n_w)); L2_STRUCT passes (P1+P2 pick (n_w=3)).
- Does mean: if you accept P, the fractions are forced and unique in R — machine-checkable.
- Does not mean: Nature must be Q₇; continuum path-integral derived P; ToE finished; PDG proves uniqueness (PDG is OUTPUT only).
6. Picture: from chaos to one map
Số Bagua thô → nhiều map (hỗn loạn)
+
Luật chơi P (STRUCT) → đúng 1 map F
+
Chứng đại số Tier-B → 3/13, 4/13, 9/40… Δ=0
+
PDG → chỉ soi gương (OUTPUT)Before the audit: “Map F looks pretty.” After: “Map F is a conditional theorem — and we know exactly what the conditions are.”
7. PDG comparison (OUTPUT only — not part of the proof)
| Quantity | F (exact) | ≈ float | Note |
|---|---|---|---|
| sin²θ_W tree | 3/13 | 0.23077 | near IR value; RG to M_Z still OPEN |
| sin²θ₁₂ | 4/13 | 0.30769 | compare NuFIT after, not as input |
| λ Cabibbo | 9/40 | 0.22500 | exact match at quoted PDG central |
| h proxy | 27/40 | 0.675 | close to h≈0.674 band |
8. Referee-safe claim (use this wording)
9. What is still open (real breakthrough targets)
- Derive P1–P2 (why 3+1+3 and (n_w=i)) from Action dynamics — not from wanting sin²θ_W ≈ 0.23.
- RG: run tree (3/13) to IR (\sin^2\theta_W(M_Z)) without hand-inserting textbook numbers.
- Keep blind predictions frozen (n_T, δ_CP, …) — do not retune after data.
10. Reproduce offline (SymPy)
Tier-B Map F kit — run these first
Each script should print OVERALL: PASS in under ~2 s after `pip install sympy`. No PDG inputs in the proof stages.
pip install sympy numpy && python3 scripts/spt_map_f_tier_b_proof.py && python3 scripts/spt_map_f_spectral_shell.py && python3 scripts/spt_map_f_uniqueness_minimal.py && python3 scripts/spt_map_f_uniqueness_enum.py && python3 scripts/spt_master_map_f_from_action.pyDon't want to install Python? Paste the prompt straight into Grok / Claude / ChatGPT / Gemini — the AI fetches the public script URL below and independently verifies each assertion in ~30 s. Open grok.com or claude.ai , paste, send.
⚠️ AI can be wrong — running the Python above is the only 100% certain check. Full AI guide →
Research notes (repo): docs/research/map-f/claim-sheet.md, smuggling-matrix.md, tier-b-proof.md.
Comments — Map F — Easy full guide: what it is, the conditions, Tier-B proof